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X^2-3X-598=0
a = 1; b = -3; c = -598;
Δ = b2-4ac
Δ = -32-4·1·(-598)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-49}{2*1}=\frac{-46}{2} =-23 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+49}{2*1}=\frac{52}{2} =26 $
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